For faster navigation, this Iframe is preloading the Wikiwand page for 闭值域定理.

闭值域定理

闭值域定理数学中的巴拿赫空间理论中的一个定理,给出了闭合稠定线性算子(closed英语Closed graph propertyDensely defined operator英语Densely defined operator)的值域为闭集的充要条件。这一定理由斯特凡·巴拿赫于1932年在《线性算子理论》(Théorie des opérations linéaires)一文中给出了证明。

XY为巴拿赫空间,若T : D(X) → Y是一个闭合的线性算子,它的定义域D(X)在X中稠密,而是它的转置算子。则定理指出,如下四个结论等价:

  • 的值域(中的闭集。
  • 的值域对偶空间中的闭集。

此定理有一些直接的推论。比如,当且仅当算子的转置存在连续的逆算子时(continuous inverse),存在一个稠定线性算子T使得Im(T) = Y。相似地,当且仅当T存在连续的逆算子时,

另见

[编辑]

参考来源

[编辑]
  • Yosida, K., Functional Analysis, Grundlehren der Mathematischen Wissenschaften (Fundamental Principles of Mathematical Sciences),vol. 123 6th, Berlin,New York: Springer-Verlag, 1980 .


{{bottomLinkPreText}} {{bottomLinkText}}
闭值域定理
Listen to this article

This browser is not supported by Wikiwand :(
Wikiwand requires a browser with modern capabilities in order to provide you with the best reading experience.
Please download and use one of the following browsers:

This article was just edited, click to reload
This article has been deleted on Wikipedia (Why?)

Back to homepage

Please click Add in the dialog above
Please click Allow in the top-left corner,
then click Install Now in the dialog
Please click Open in the download dialog,
then click Install
Please click the "Downloads" icon in the Safari toolbar, open the first download in the list,
then click Install
{{::$root.activation.text}}

Install Wikiwand

Install on Chrome Install on Firefox
Don't forget to rate us

Tell your friends about Wikiwand!

Gmail Facebook Twitter Link

Enjoying Wikiwand?

Tell your friends and spread the love:
Share on Gmail Share on Facebook Share on Twitter Share on Buffer

Our magic isn't perfect

You can help our automatic cover photo selection by reporting an unsuitable photo.

This photo is visually disturbing This photo is not a good choice

Thank you for helping!


Your input will affect cover photo selection, along with input from other users.

X

Get ready for Wikiwand 2.0 🎉! the new version arrives on September 1st! Don't want to wait?