${\displaystyle a\in (\dots ,-2,-1,0,1,2,\dots )}$
${\displaystyle b\in (\dots ,-2,-1,0,1,2,\dots )}$
${\displaystyle n=b-a+1}$

${\displaystyle k\in \{a,a+1,\dots ,b-1,b\))$

${\displaystyle {\begin{matrix}{\frac {1}{n))&{\mbox{dla ))a\leqslant k\leqslant b,\ k\in {\mathbb {Z} }\\0&{\mbox{w przeciwnym wypadku))\end{matrix))}$

${\displaystyle {\begin{matrix}0&{\mbox{dla ))k<a\\{\frac {\lfloor k\rfloor -a+1}{n))&{\mbox{dla ))a\leqslant k\leqslant b\\1&{\mbox{dla ))k>b\end{matrix))}$

${\displaystyle {\frac {a+b}{2))}$

${\displaystyle {\frac {a+b}{2))}$

N/A

${\displaystyle {\frac {n^{2}-1}{12))}$

${\displaystyle 0}$

${\displaystyle -{\frac {6(n^{2}+1)}{5(n^{2}-1)))}$

${\displaystyle \ln(n)}$

${\displaystyle {\frac {e^{at}-e^{(b+1)t)){n(1-e^{t})))}$

${\displaystyle {\frac {e^{iat}-e^{i(b+1)t)){n(1-e^{it})))}$