A, B, ν

${\displaystyle f(x)={\frac {\left({\frac {x-A}{B))\right)^{\nu -1}e^{-{\frac {1}{2))\left({\frac {x-A}{B))\right)^{2))}{2^((\frac {\nu }{2))-1}B\Gamma \left({\frac {\nu }{2))\right)))}$

${\displaystyle F(x)=\Gamma \left({\frac {\nu }{2)),{\frac {1}{2))\left({\frac {x-A}{B))\right)^{2}\right)}$

${\displaystyle A+{\frac ((\sqrt {2))B\Gamma \left({\frac {\nu +1}{2))\right)}{\Gamma \left({\frac {\nu }{2))\right)))}$

nie może być wyrażona za pomocą funkcji elementarnych

${\displaystyle A+B{\sqrt {\nu -1))}$

${\displaystyle B^{2}\left[\nu -{\frac {2\Gamma ^{2}\left({\frac {\nu +1}{2))\right)}{\Gamma ^{2}\left({\frac {\nu }{2))\right)))\right]}$

${\displaystyle {\frac ((\sqrt {2))\left[4\Gamma ^{3}\left({\frac {\nu +1}{2))\right)+\Gamma ^{2}\left({\frac {\nu }{2))\right)\left(2\Gamma \left({\frac {\nu +3}{2))\right)-3\nu \Gamma \left({\frac {\nu +1}{2))\right)\right)\right]}{\Gamma ^{3}\left({\frac {\nu }{2))\right)\left[\nu -{\frac {2\Gamma ^{2}\left({\frac {\nu +1}{2))\right)}{\Gamma ^{2}\left({\frac {\nu }{2))\right)))\right]^{\frac {3}{2))))}$

${\displaystyle {\frac {2\nu (1-\nu )\Gamma ^{4}\left({\frac {\nu }{2))\right)-24\Gamma ^{4}\left({\frac {\nu +1}{2))\right)}{\left[\nu \Gamma ^{2}\left({\frac {\nu }{2))\right)-2\Gamma ^{2}\left({\frac {\nu +1}{2))\right)\right]^{2))}+}$
${\displaystyle +{\frac {8(2\nu -1)\Gamma ^{2}\left({\frac {\nu }{2))\right)\Gamma ^{2}\left({\frac {\nu +1}{2))\right)}{\left[\nu \Gamma ^{2}\left({\frac {\nu }{2))\right)-2\Gamma ^{2}\left({\frac {\nu +1}{2))\right)\right]^{2))))$