1852 United States presidential election in Missouri
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| Elections in Missouri |
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The 1852 United States presidential election in Missouri took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose nine representatives, or electors to the Electoral College, who voted for President and Vice President.
Missouri voted for the Democratic candidate, Franklin Pierce, over Whig candidate Winfield Scott. Pierce won Missouri by a margin of 12.84%.
Results
[edit]| 1852 United States presidential election in Missouri[1][2] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Democratic | Franklin Pierce of New Hampshire | William R. King of Alabama | 38,817 | 56.42% | 9 | 100.00% | ||
| Whig | Winfield Scott of New Jersey | William A. Graham of North Carolina | 29,984 | 43.58% | 0 | 0.00% | ||
| Total | 68,801 | 100.00% | 9 | 100.00% | ||||
See also
[edit]References
[edit]- ^ "1852 Presidential General Election Results - Missouri". U.S. Election Atlas. Retrieved December 2, 2017.
- ^ "1852 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved December 2, 2017.
Recent elections in Missouri | |
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| Governor | |
| Lieutenant Governor | |
| Attorney General | |
| State Auditor | |
| State Treasurer | |
| Secretary of State | |
| MO Senate | |
| MO House of Representatives | |
| U.S. President | |
| U.S. Senate | |
| U.S. House of Representatives | |
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